0 like 0 dislike
20 views

The first four terms of a sequence are given

$$\frac{2}{1 \times 2} ; \frac{2}{2 \times 3} ; \frac{2}{3 \times 4} ; \frac{2}{4 \times 5}$$

1. Write down the next two terms of the sequence
2. Determine the nth term of the sequence.
3. Use the answer in the previous question to calculate n if the nth term is $\frac{1}{66}$
| 20 views

0 like 0 dislike
1. 2/(5 x 6) ; 2/(6 x 7)

2. 2/(n-1)(n-2)

3. 2/(n-1)(n-2) = 1/66  , then expand and solve for n,

n^2 -3n -130=0

(n-13)(n+10)=0

n= 13 or -10

but n be positive, n=13
by Silver Status (28.5k points)

0 like 0 dislike