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For each trip, a taxicab company charges \$4.25 for the first kilometre and \$2.65 for each additional km or fraction thereof.​ If the total charge for a certain trip was \$62.55, how many km at most was the trip?
in Mathematics Anonymous by Diamond (37.9k points) | 30 views

1 Answer

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If total distance of trip is x,

4.25 + 2.65x = 62.55

2.65x = 62.55 - 4.25 = 58.3

x = 58.3 / 2.65 = 22

Therefore the trip was at most 22km.
by Wooden (4.6k points)
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