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Solve for x, rounded off to TWO decimal places where necessary:

1. $x^{2} = 5x -4$
2. $x(3-x) = -3$
3. $3 - x < 2x^{2}$
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1. x^2 -5x+4x   substitute into quadratic formula since answers may be in decimal fraction form, however the formula can solve all quadratic equations

x=4 or x=1

2. x^2-3x-3=0, x=3.79 or x= -0.79

3. 2x^2+x-3>0      solve as an equation to find critical values(>=)

x=1 or x= -1.5   use number line to find where the values satisfy the inequality

x>1 and x< -1.5    = -1.5>x>1

by Diamond (84.9k points)

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