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A rider in a balloon throws a water balloon from the balloon basket backwards to hit a target directly under him at the time of release. The splat is seen 3.5 seconds later when the balloon is 50m away from the target. In order to hit the intended target, how fast must he throw the balloon backwards?
in Grade 12 Physical Sciences by Platinum (112k points) | 16 views

1 Answer

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v= r/t

= (50/2)/3.5

= 7.14 m/s
by Bronze Status (6.9k points)
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