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Simplify $\ln e^5$
in Grade 12 Maths by Wooden (1.7k points)
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ln e is equal to log e base e

 

by Wooden (1.7k points)
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The natural log of e itself, ln(e), is 1, because e1 = e, while the natural logarithm of 1, ln(1), is 0, since e0 = 1.

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