0 like 0 dislike
19 views
Determine the values of $p\;$ for which the function $$f(x) = 3p ^3 - (3p-7)x^2 + 5x - 3$$ leaves a remainder of $9$ when it is divided by $(x-p)$
| 19 views

0 like 0 dislike
x=p

f(x)= 3p^3 - (3p-7)p^2 + 5p -3 = 9

3p^3-3p^3+7p^2+5p-12=0

7p^2+5p -12=0    factorize

(7p+12)(p-1)=0

p= -12/7= -1 5/7    or p=1
by Diamond (80.1k points)

0 like 0 dislike