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Solve for $x$: $x^3 - x^2 = 3(3x + 2)$
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expand, equate to zero and find value of x from 1 to about 3 or so, that can give zero when substituted.

x= -2 gives 0

then do long division: x+2 into x^3 - x^2 -9x - 6

(x+2)(x^2-3x-3)=0   , use quadratic formula for the 2nd bracket as it cant be factorized

x = -2 or x= 3.79 or x= -0.79
by Diamond (80.1k points)