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Find $f^{\prime}(x)$ for each of the following:

  1. $f(x) = \dfrac{\sqrt[5]{x^3}}{3} + 10$
  2. $f(x) = \dfrac{(2x^2 - 5)(3x + 2)}{x^2}$
in Grade 12 Maths by Bronze Status (5.9k points) | 15 views

1 Answer

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1. = [x^(3/5)]/3 +10

dy/dx = 1/[5.fifthroot(x)^2]

2. (6x^3 + 4x^2 - 15x -10)/x^2  , then divide separately by x^2

 = 6x+4-15x^-1 -10x^-2

dy/dx = 6+15x^-2 + 20x^-3

    =  6 + 15/x^2 + 20/x^3
by Diamond (82.9k points)

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