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Given: $f(x)=2x^2-x$

  1. Use the definition of the derivative to calculate $f'(x)$.
  2. Hence, calculate the co-ordinates of the point at which the gradient of the tangent to the graph of $f$ is $7$.
in Grade 12 Maths by Bronze Status (5.9k points) | 14 views

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1. dy/dx = 4x -1 which is gradient

2. 4x-1=7

       x= 2

y= 2(2)^2 - 2 =6

   (2;6) point
by Diamond (82.9k points)

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