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Prove that  $\sin^3\theta=\frac{3\sin\theta-\sin 3\theta}{4}$
in Grade 12 Maths by Bronze Status (5.9k points) | 13 views

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= 3sinx/4 - sin3x/4 = 1/4(sinx^3 - sin2(1.5x)  use double angles

                              = sinx^3
by Diamond (82.9k points)

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