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${45}{C}$ of electrical charge leave a ${9}{V}$ battery. How much energy does this charge carry?
in Grade 12 Physical Sciences by Platinum (110k points) | 16 views

2 Answers

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E= V*Q

=(9)*(45)

=405 J
by Bronze Status (6.9k points)
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V = 9 V    E(W) = ?    q = 45

V = E(W) / q

E(W) = V x q

E(W) = 9 x 45

E(W) = 405 J
by Wooden (3.1k points)

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