1. dy/dx = 6x^2 -10x -4 = 0 at stationary points

(6x+2)(x-2)=0

x = -1/3 or 2

substitute x values into cubic function, y = 3.7 or -9

= (-1/3;3.7) and (2;-9)

Point of inflection = (-1/3 + 2)/2 ; (3.7 +(-9))/2 = (0.83;-2.65)

2. Let x=0, y=3 for y-intercept

x-intercepts are given

Coordinates of turning points and inflection already calculated from 1.

The cubic graph will decrease from left, increase and decrease, as coefficient of x^3 is positive.

3. dy/dx at x = 1, = 6(1)^2 - 10(1)-4

= 6-10-4

= -8

substituting x=1 into cubic graph, y= -4

hence y-(-4)= -8(x-1)

y= -8x +4