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Given $\log_3 6 = a$ and $\log_6 5 = b$

1. Express $\log_3 2$ in terms of $a$.
2. Hence, or otherwise, find $\log_3 10$ in terms of $a$ and $b$.
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1. log(3 x 2) = a

log3 + log2 = a

log2 = a - log3

2. log10= log(5 x 2)

= log5 + log2

= b + a - log3

= a + b - log3
by Diamond (82.9k points)